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Ammonium nitrate (NH4NO3) is a common component of fertilizer because it is a great source of two nitrogen-containing ions that easily dissolve into water. A large batch of this liquid fertilizer is made by adding 2.13 pounds of ammonium nitrate to 26.00 gallons of water. What is the molarity of this solution? (Hint: 1 lb. = 454 g and 1 gal. = 3.79 L.)

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samueladesida43

Answer:

0.123 M

Explanation:

Molarity, which is molar concentration can be calculated by using the formula;

Molarity = number of moles (n) / Volume (V)

Number of moles of NH4NO3 can be calculated by using;

Mole = mass (M) / Molar mass (MM)

Since atomic mass of N= 14, H=1, O=16

Molar mass of NH4NO3 = 14 + 1(4) + 14 + 16(3)

= 14 + 4 + 14 + 48

= 80g/mol

1 pounds = 454g

2.13 pounds= 2.13 × 454 g

= 967.02g

Hence; mole of NH4NO3 = 967.02/80

= 12.09moles

Molarity of NH4NO3 in water (solution) = number of moles of NH4NO3 ÷ volume of water

1 gallon = 3.79Litres

26gallons = 26 × 3.79 litres

= 98.54 Litres

Therefore, Molarity = 12.09/98.54

Molarity of NH4NO3 solution = 0.1226

= 0.123M or mol/L

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