Answer:
w = 4.712 10⁻³ rad / s
Explanation:
For this exercise, the time it takes for the bullet to travel the distance of 2R must be equal to the time that the hole must travel half a circle.
Let's start by calculating the time it takes for the bullet, which is going at constant speed.
v = x / t
t = x / v
t = 2R / v
t = 2 0.10 / 300
t = 6.666 10⁻⁴ s
As they ask that a single hole is formed in this time, it must be rotated half a circle, that is, θ =π rad, for which we use the angular scientific relations, where the shell has constant angular velocity
w = θ / t
w = π / 6,666 10⁻⁴
w = 4.712 10⁻³ rad / s
