Answer:
12 grams
Explanation:
For any radioactive substance
the amount of substance left after n half life is given by = [tex]x/2^n[/tex]
where x the original amount of substance.
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Half life of isotope Np-238 = 2 days
total no of days = 6
no of half life =total no of days/Half life of isotope Np-238 = 6/2 = 3
thus,
for our problem n = 3
initial amount of Np-238 = 96 grams
thus,
the amount of substance left after 3 half life = 96/2^3 = 96/8 = 12 grams.
Thus, 12 grams will be left after six days.
