joziahj04
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An eraser is thrown upward with an initial velocity of 5.0 m/s. The eraser's velocity after 7.0 seconds is ____ m/s.
Answer: -64

Respuesta :

quasarJose

Given parameters:

Initial velocity of eraser  = 5.0m/s

Time  = 7.0s

Unknown:

Final velocity = ?

Solution:

Since we have been given the initial velocity and duration of the throw, we can apply the appropriate motion equation to solve this problem.

       V  = U - 2gt

where V is the final velocity

            U is the initial velocity

             g is the acceleration due to gravity = 9.8m/s²

            t is the time taken

       V  = U - gt

       V = 5 - (9.8)(7)

       V = -63.6 or -64m/s

The velocity is -64m/s

   

nuhulawal20

As the eraser is thrown upward, its velocity after 7.0 seconds is approximately -64m/s.

Given the data in the question;

Initial velocity of the eraser; [tex]u = 5.0m/s[/tex]

Final velocity; [tex]v = \ ?[/tex]

Time; [tex]t = 7.0s[/tex]

To determine the eraser's velocity after 7.0 seconds, we us the First Equation of Motion:

[tex]v = u + at[/tex]

Where v is the final velocity, u is the initial velocity, t is the time and a is the acceleration. Since the eraser was thrown upward, acceleration due to gravity becomes ( negative acceleration ) [tex]g = -9.8m/s^2[/tex]

Hence, the equation becomes

[tex]v = u - gt[/tex]

We substitute in our values and solve for "v"

[tex]v = 5.0m/s - ( 9.8m/s^2 \ *\ 7.0s )\\\\v = 5.0m/s - 68.6m/s\\\\v = -63.6m/s\\\\v = -64m/s[/tex]

Therefore, as the eraser is thrown upward, its velocity after 7.0 seconds is approximately -64m/s.

Learn more; https://brainly.com/question/9240794

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