What is the slope of this line?



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$\text{Basic}$
$x$y$x^2$\sqrt{ }$\frac{x}{ }$
$x\frac{ }{ }$
$x^{ }$x_{ }$\degree$\left(\right)$\abs{ }$\pi$\infty$

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Answer:

Slope = 6

Step-by-step explanation:

Reading your description carefully, the equation of line has been given to be

When we compare this with the standard form of a straight line

We immediately see that the slope or gradient m = 6.

Alternatively, when we consider the coordinates of the points mentioned, we have

(1, 5)    ;     (0, -1)     ;     (-1, -7)

We can take any two points out of these three and calculate the slope using the formula

For example, let us consider the points (1, 5) and (-1, -7)

Here x₁ = 1; x₂ = -1 and y₁ = 5; y₂ = -7

Plugging the numbers in the above formula, we have

This agrees with what we calculated directly from the equation of the line!

Hence, slope of the line on the graph = 6

The slope of the line in simplified form is -1

Find the required diagram attached.

The formula for calculating the slope of a line is expressed as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Using the coordinate points (0, -2) and (-2, 0)

Substitute the given coordinates into the formula:

[tex]m=\frac{0-(-2)}{-2-0}\\m=\frac{0+2}{-2}\\m=\frac{-2}{2}\\m=-1[/tex]

Hence the slope of the line in simplified form is -1

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