Answer:
473 °C
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 200 mL
Initial temperature (T1) = 100 °C
Final volume (V2) = 400 mL
Final temperature (T2) =..?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T (°C) + 273
Initial temperature (T1) = 100 °C
Initial temperature (T1) = 100 °C + 273 = 373 K
Next, we shall determine the final temperature of the water as follow:
Initial volume (V1) = 200 mL
Initial temperature (T1) = 373 K
Final volume (V2) = 400 mL
Final temperature (T2) =..?
V1/T1 = V2/T2
200/373 = 400/T2
Cross multiply
200 × T2 = 373 × 400
200 × T2 = 149200
Divide both side by 200
T2 = 149200/200
T2 = 746 K
Finally, we shall convert 746 K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T(K) = 746 K
T(°C) = 746 – 273
T(°C) = 473 °C
Therefore, the temperature of the second sample when it starts to boil is 473 °C
