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The perimeter of a rectangle is found by multiplying the sum of the length, shown as LaTeX: ll, and the width, shown as LaTeX: ww, by LaTeX: 22. The length of a certain rectangle is LaTeX: 2020 . Which inequality shows that the perimeter of this rectangle is less than LaTeX: 5757 units?

Respuesta :

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Answer:

40 + 2W < 57

Step-by-step explanation:

Given that:

Perimeter of a rectangle (P) :

P = 2(length(L) + width(W))

If the length of a certain rectangle L = 20 ; which inequality shows perimeter of rectangle is less than 57 units

P = 2(length(L) + width(W))

40 + 2W < 57

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