Answer:
The coefficient of kinetic friction [tex]\mu_k = 0.724[/tex]
Explanation:
From the question we are told that
The length of the lane is [tex]l = 36.0 \ m[/tex]
The speed of the truck is [tex]v = 22.6\ m/s[/tex]
Generally from the work-energy theorem we have that
[tex]\Delta KE = N * \mu_k * l[/tex]
Here N is the normal force acting on the truck which is mathematically represented as
[tex]\Delta KE[/tex] is the change in kinetic energy which is mathematically represented as
[tex]\Delta KE = \frac{1}{2} * m * v^2 [/tex]
=> [tex]\Delta KE = 0.5 * m * 22.6^2 [/tex]
=> [tex]\Delta KE = 255.38m [/tex]
[tex] 255.38m = m * 9.8 * \mu_k * 36.0 [/tex]
=> [tex] 255.38 = 352.8 * \mu_k [/tex]
=> [tex]\mu_k = 0.724[/tex]
