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Genevieve has $9000 to invest. She invests some at 6% annual interest and the rest at 4% annual interest. After one year, her total interest from both accounts is $444. How much did she invest in each account? (Clearly label which amount is for which account in your answer. Hint: Over a one year period, annual interest is the same as simple interest.)

Respuesta :

AayushTripathy

Answer:

The first account, she invested = $4200 and in the second = $4800

Step-by-step explanation:

Let us assume that Genevieve invests $x at 6% ,

Hence, she invests ($9000 - $x ) at 4% ,

It's given that the combined interest from both of the above accounts is $444,

So,

0.06x + 0.04 (9000 - x) = 444

=> 0.06x + 360 - 0.04x = 444

=> (0.06x - 0.04x) + 360 = 444

=> 0.02x = 444 - 360

=> 0.02x = 84

=> x = 84/0.02

=> x = 8400/2 (By multiplying the denominator and numerator)

=> x = 4200

Therefore, 9000 - x = 9000 - 4200 = 4800

$4200 at 6% and $4800 at 4%

Therefore, the first account, she invested = $4200 and in the second = $4800

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