Answer:
Clay's finishing time is 1.68 standard deviation above the mean finishing time for men.
Step-by-step explanation:
In statistics, a standardized score is the number of standard deviations an observation or data point is from the mean.
Let us consider a random variable, X that follows a normal distribution, N (µ, σ²).
Then Z is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is,
[tex]Z=\frac{x-\mu}{\sigma}\sim N(0, 1)[/tex]
This, z-score is known as the standardized score.
It is provided that the distribution of finishing time for men (say, X) was approximately normal with mean µ = 242 minutes and standard deviation σ = 29 minutes.
The finishing time for Clay was x = 289 minutes.
Compute Clay's z-score as follows:
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]=\frac{289-242}{29}\\\\=1.67857143\\\\\approx 1.68[/tex]
Thus, Clay's standardized score is 1.68.
That is, Clay's finishing time is 1.68 standard deviation above the mean finishing time for men.