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In a population of frogs, there is a dominant allele H that improves the survival of eggs in moderately dry conditions compared to the wild-type and recessive h allele. Imagine that climate change causes the environment where these frogs live to become more dry. Individuals with the drought-resistant eggs on average have 21 viable offspring per frog per generation, whereas those without that phenotype on average have only 12. If we start off with genotype frequencies of .02 HH, .03 Hh, and .95 hh, what is the average excess fitness of the H allele?

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ogorwyne

Answer:

8.55

Explanation:

I n the year1908, these two men Godfrey Hardy and Wilhelm Weinberg gave a specification of the relationship between the frequency of genotype and frequencies of allele that should occur when such a population is in equilibrium

p²+2pq+q² = 1

we have,

p² = 0.02

p = √0.02

such that frequency of H is = 0.1414

2pq = 0.03

q² = 0.95

q= √0.95

such that frequency of h =0.9746

(21-12)  * 0.95 =

8.55 frogs per generation

H and h will coexist.

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