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The management of Hartman Rent-A-Car has allocated $2.52 million to buy a fleet of new automobiles consisting of compact, intermediate-size, and full-size cars. Compacts cost $18,000 each, intermediate-size cars cost $27,000 each, and full-size cars cost $36,000 each. If Hartman purchases twice as many compacts as intermediate-size cars and the total number of cars to be purchased is 100, determine how many cars of each type will be purchased. (Assume that the entire budget will be used. Let x, y, and z denote the number of compact, intermediate-sized, and full-size cars purchased, respectively.)

Respuesta :

Answer:

The number of compact cars = x = 30 cars

The number of intermediate-sized car = y = 60 cars

The number of full-size cars purchased = z = 10 cars

Step-by-step explanation:

Let us denote:

the number of compact car = x

the number of intermediate-sized car = y

the number of full-size cars purchased = z

The total number of cars to be purchased is 100.

Hence:

x + y + z = 100...........Equation 1

If Hartman purchases twice as many compacts as intermediate-size cars

y = 2x

So: x + 2x + z = 100..........Equation 2

= 3x + z = 100

z = 100 - 3x

Compacts cost $18,000 each, Intermediate-size cars cost $27,000

Full-size cars cost $36,000 each.

Assume that the entire budget will be used.

Hence,

x × $18,000 + y × $27,000 + z × $36,000 = $2,520,000.

18000x + 27000y + 36,000z = $2,520,000.....Equation 4

Substitute 100 - 3x for z and y = 2x in Equation 4

18000x + 27000(2x) + 36,000(100 - 3x) = $2520000

18000x + 54000x + 3,600,000 -108000x = $2520000

72000x -108000x + 3,600,000 = $2,520,000

= $3,600,000 - $2,520,000 = 108000x - 72,000x

$1,080,000 = 36,000x

Divide both sides by $36,000

x = $1080000/36000

x = 30

From the above:

y = 2x

y = 2 × 30

= 60

z = 100 - 3x

= 100 - 3 × 30

= 100 - 90

= 10

Therefore,

The number of compact cars = x = 30 cars

The number of intermediate-sized car = y = 60 cars

The number of full-size cars purchased = z = 10 cars

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