wendreycalinog7
contestada

from problem 2,suppose another boy, boy C pulls the heavy cabinet with 5N of force in the same direction with boy A

1. what will be the net foece on the cabinet?
2. will the cabinet move?
3. in what direction will the cabinet move?​

Respuesta :

whitneytr12

Answer:

Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.  

1. F = 10 N

2. Yes, it will move.

3.  It will move to the left direction of the cabinet (same direction as the boys A and C).

           

Explanation:

Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.  

1. Hence, if another boy (C) pull in the same direction as the boy A with 5 N of force, we have:

[tex] \Sigma F = F_{A} + F_{C} - F_{B} [/tex]

[tex] \Sigma F = 10 N + 5 N - 5 N = 10 N [/tex]

The net force on the cabinet is 10 N.

2. Yes, the cabinet will move. From point 1 we can deduce that the cabinet will move since the net force on the cabinet is different from zero (10 N).                    

3. The direction of the motion is the same as the Boys A and C, that is to say, to the left of the cabinet.      

I hope it helps you!

The net force acting on an object, is the vector sum of all the forces acting on it

The correct values for the forces acting on the cabinet are;

1. The net force on the cabinet is 10 N

2. Yes, the cabinet will move

3. The cabinet will move in the direction of boy A and boy C

The reason the above values are correct are as follows:

Question: The possible missing part of the question is; In problem 2 boy A is pulling a heavy cabinet with [tex]F_A[/tex] = 10 N force, and boy B is pulling the same cabinet at the same time and in opposite direction with a force of [tex]F_B[/tex] = 5 N

The known parameter:

The force with which boy C pulls the heavy cabinet = 5 N

The direction in which boy C pulls the cabinet = The same direction as boy A

Question 1. The net force on the cabinet, [tex]F_{NET}[/tex] is given as follows;

Taking the direction of the force of boy A as the positive direction, we have;

[tex]\overset \longrightarrow {F_A}[/tex] = 10 N

[tex]\overset \longrightarrow {F_B}[/tex] = - 5 N

[tex]\overset \longrightarrow {F_C}[/tex] = 5 N

[tex]\overset \longrightarrow {F_{NET}}[/tex] = [tex]\overset \longrightarrow {F_A}[/tex] + [tex]\overset \longrightarrow {F_B}[/tex] + [tex]\overset \longrightarrow {F_C}[/tex]

[tex]\overset \longrightarrow {F_{NET}}[/tex] = 10 N + (-5 N) + 5 N = 10 N

The net force on the cabinet, [tex]\overset \longrightarrow {F_{NET}}[/tex] = 10 N

Question 2. Yes: Given that there is a net force acting on the cabinet, according to Newton's first law of motion, in the absence of friction force, the cabinet will move in the direction of the net force of 10 Newton

Question 3. The cabinet will move in the direction of the net fore

The direction of the net force is the direction boy A and boy C are pulling the cabinet

Therefore, the cabinet will move in the direction boy A and boy C are pulling the heavy cabinet

Learn more about addition of forces here:

https://brainly.com/question/2080520

Ver imagen oeerivona

Otras preguntas