Respuesta :
Answer:
The sample which would contain more oxygen atoms is a glass stirring rod.
Explanation:
According to the periodic table ,
the glass stirring rod is Silicon dioxide and the cotton ball is cellulose
Here , the molar mass of the glass stirring rod [tex]SiO_{2}[/tex] = 60.08 Grams/mole
Molar mass of the cotton ball [tex]C_{6} H_{10}O_{5}[/tex] = 162.09 gram/mole .
since ,total number of molecules present in oxygen is 32 ,
therefore ,
In glass stirring rod ,
number of oxygen atoms present in 5g = [tex]\frac{32}{60.07} \times 5[/tex]
= 2.66 g of oxygen
[tex]\frac{1}{16} \times 2.66[/tex]
= 0.16625 moles
= 0.16625 x [tex]6.023\times 10^{23}[/tex]
=[tex]1.001 \times10^{23}[/tex] atoms
In cotton ball ,
number of oxygen atoms present in 5g = [tex]\frac{80}{162.09} \times 5[/tex]
= 2.467 g of oxygen
[tex]\frac{1}{16} \times 2.467[/tex]
= 0.15418 moles
= 0.15418 [tex]\times 6.023 \times 10^{23}[/tex]
= 0.928 [tex]\\ \times10^{23}[/tex]
Hence , the glass stirring rod contains more number of oxygen atoms .
