Your answer can be anything in the form y = mx+8 where you replace m with any real number.
You start with y = mx+b, and then replace the b with the y intercept 8.
The y intercept is where the polynomial crosses the y axis.
The value of m does not matter. So you could have y = 2x+8 or y = 3x+8 for instance. Replace m with whatever your favorite number is.
We want to find a polynomial of 1st degree that passes through the y-axis at y = 8.
The polynomial is: y = a*x + 8
Where the coefficient a can be any real number different than zero.
Let's see how to find that polynomial.
Remember that the degree of a polynomial gives us information of the maximum exponent that the polynomial has.
So if the degree is 1, then the polynomial maximum exponent is 1.
From this we can conclude that the polynomial will be something like:
y = a*x + b
Now, this is just a linear equation, where a is the slope and b is the y-intercept.
We do know that this intercepts the y-axis at 8, then we define b = 8, and we get:
y = a*x + 8
This is our polynomial, where the value of a can be any real number different than zero (we use that restriction because if a = 0, then the degree of the polynomial would not be 1).
If you want to learn more, you can read:
https://brainly.com/question/15522547
