Answer:
We have two consecutive even integers:
a and b.
We know that we can write a even integer as:
a = 2*n
where n is an integer.
Then the consecutive integer to a, b, will be:
b = 2*n + 2.
Then the sum of a and b is:
a + b = 2n + 2n + 2 = 4*n + 2 = 2*(2n + 1) = k.
The next two consecutive integers greater than b will be:
c = 2n + 4
d = 2n + 6
then:
c + d = (2n + 4) + (2n + 6) = 4n + 10 = k + 4.
