Respuesta :
x - Ernie, y - Kaylin, z - Tria
x = y + 121.50
z = 3y - 35
x + y + z = 579
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z = 3 y - 35 => - 3 y + z = -35
y + 121.50 + y + z = 579
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- 3 y + z = - 35 / · ( -1 )
2 y + z = 457.50 (we will use the elimination method)
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3 y - z = 35
2 y + z = 457.50
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5 y = 492.5, y = 492.5 : 5 = 98.5
z = 3 · 98.5 - 35
z = 260.5
Tria earned $260.5
C)260.50
Step by step explanation
Let "x" be the amount earned by Ernie
Let "y" be the amount earned by Kaylin
Let "z” be the amount earned by Tria
Now let’s form the equations
x=y + 121.50 (1)
z=3y- 35 (2)
x + y + 2= 579 (3)
Now plug in x = y + 121.50, in the third equation.
y + 121.50 + y + z =579
2y + z = 457.50
From the second equation 3y - z = 35
2y + z =457.50
3y - z = 35
5y = 492.5
Dividing both sides by 5 we get
y = 98.50
Now let’s find how much Tria earned.
z = 3*98.5 - 35
z = $260.50
Step by step explanation
Let "x" be the amount earned by Ernie
Let "y" be the amount earned by Kaylin
Let "z” be the amount earned by Tria
Now let’s form the equations
x=y + 121.50 (1)
z=3y- 35 (2)
x + y + 2= 579 (3)
Now plug in x = y + 121.50, in the third equation.
y + 121.50 + y + z =579
2y + z = 457.50
From the second equation 3y - z = 35
2y + z =457.50
3y - z = 35
5y = 492.5
Dividing both sides by 5 we get
y = 98.50
Now let’s find how much Tria earned.
z = 3*98.5 - 35
z = $260.50