Answer:
2.8 [N] at 163° counterclockwise from F1
Explanation:
To solve this problem we must perform a summation of forces on the X & y axes, these summations of forces must be equal to zero.
ΣFx = 0
- F1 + Fx = 0
- 2.7 + Fx = 0
Fx = 2.7 [N]
ΣFy = 0
- Fy + 0.8 = 0
Fy = 0.8 [N]
Now using the Pythagorean theorem we can calculate the magnitude of the force.
F = √(2.7)² + (0.8)²
F = 2.81 [N]
Now we can determine the angle using the tangent of the angle.
tan (α) = F2/F1
α = tan^-1 (0.8/2.7)
α = 16.5°
The force is in the fourth quadrant, so we need to subtract 180° from the calculated angle.
180 - 16.5 = 163.5°
Therefore the force is going to the 2.8 [N] at 163° counterclockwise from F1
