how much time does it required for an airplane to reach its take off speed of 77 m/s if it starts from rest and its average acceleration is 8.2 m/s^2

Respuesta :

Answer:

t = 9.38 seconds

Explanation:

Given that,

Initial speed of the airplane, u = 0 (at rest)

Final speed of the airplane, v = 77 m/s

Acceleration of the airplane, a = 8.2 m/s²

We need to find the time required for the airplane to accelerate. The formula of acceleration is given by :

[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{77-0}{8.2}\\\\t=9.38\ s[/tex]

So, the time taken by the airplane is 9.38 seconds.