Respuesta :
Answer:
9.033 × 10²³ molec C₂HF₃O₂ x (2 O atoms / 1 molec C₂HF₃O₂) = 1.8066 x 10²⁴ O atoms
There are 3.01 × 10^23 atoms of oxygen in 1.51×10^23 molecules of trifluoroacetic acid, C2HF3O2.
The formula of trifluoroacetic acid is C2HF3O2
Number of moles of the trifluoroacetic acid(C2HF3O2)is given using the approach;
1 mole of the compound contains 6.02 × 10^23 molecules
x moles of the compound contains 1.51 × 10^23 molecules
x = 1.51 × 10^23 molecules × 1 mole /6.02 × 10^23 molecules
x = 0.25 moles of trifluoroacetic acid.
Now;
Number of O atoms in the sample = 0.25 × 2 × NA
Where; NA = Avogadro's number
Number of O atoms in the sample = 0.25 × 2 × 6.02 × 10^23 atoms
= 3.01 × 10^23 atoms
Learn more: https://brainly.com/question/24798986