Answer:
[tex]2\frac{13}{120}[/tex]
Step-by-step explanation:
**Fractions for addition and/or subtraction need equal denominators
Alike denominators in parentheses
[tex]4\frac{2}{5} -(1\frac{2}{3}+\frac{5}{8})\\4\frac{2}{5} -(1\frac{2}{3}(\frac{8}{8}) +\frac{5}{8}(\frac{3}{3} ))\\4\frac{2}{5}-(1\frac{16}{24}+\frac{15}{24})\\4\frac{3}{5} -(1\frac{31}{24} )\\4\frac{3}{5} -(2\frac{7}{24} )[/tex]
[tex]4\frac{2}{5}-2\frac{7}{24}[/tex]
Solve
[tex]4\frac{2}{5}-2\frac{7}{24} \\4\frac{2}{5}(\frac{24}{24}) -2\frac{7}{24}(\frac{5}{5})\\4\frac{48}{120}-2\frac{35}{120}\\2\frac{13}{120}[/tex]
