Respuesta :
Given parameters:
Frequency of the wave = 1520kHz = 1520 x 10³Hz
Unknown:
Wavelength of the radio photon = ?
Energy of the wave = ?
Solution:
The wavelength of any electromagnetic wave can found using the expression below;
C = f x ∧
Where C is the velocity of light = 3 x 10⁸m/s
f is the frequency of the wave
∧ is the wavelength
Since the unknown is ∧, input the known parameters and solve for it;
3 x 10⁸ = 1520 x 10³ x ∧
Wavelength = [tex]\frac{3 x 10^{8} }{1520 x 10^{3} }[/tex]
Wavelength = [tex]\frac{3 x 10^{8} }{1.52 x 10^{6} }[/tex]
Wavelength = 1.97 x 10²m
ii. Energy of the wave;
Energy of a wave = hf
where h is the planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹
f is the frequency of the wave
Input the parameters and solve;
Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶
= 10.1 x 10⁻²⁸J
The energy of this wave is 10.1 x 10⁻²⁸J
Wavelength of the wave = 1.97 x 10²m
Energy of the wave = 10.1 x 10⁻²⁸J
Given:
Frequency of the wave = 1520kHz = 1520 x 10³Hz
To find:
Wavelength of the radio photon = ?
Energy of the wave = ?
Calculation of Wavelength:
The wavelength of any electromagnetic wave can found using the expression below:
c = f * ∧
Where,
c is the velocity of light = 3 x 10⁸m/s
f is the frequency of the wave
∧ is the wavelength
On substituting the values:
3 x 10⁸ = 1520 x 10³ x ∧
Wavelength = 1.97 x 10²m
Calculation of Energy of the wave:
Energy of a wave = h*f
where,
h is the Planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹
f is the frequency of the wave
On substituting the values:
Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶
Energy of the wave = 10.1 x 10⁻²⁸J
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