Find the value of x in the equation without evaluating the power

Step-by-step explanation:
a)2^8=256
2^5*2^x=2^8
5+x=8
x=8-5
x=3
b)(1/3)^6
(1/3)^2*(1/3)^x=(1/3)^6
2+x=6
x=6-2
x=4
therefore the value of x in a is 3
and the value of x in b is 4
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a) The value of x is 3
b) The value of x is 5
Given the expression [tex]2^5\cdot 2^x = 256[/tex]
Using the law of indices, the equation becomes;
[tex]2^{5+x} = 2^8\\5 + x = 8\\x = 8 -5 \\x = 3[/tex]
Hence the value of x is 3
b)
[tex](\frac{1}{3})^2 \cdot (\frac{1}{3})^x = (\frac{1}{729})\\(\frac{1}{3})^{2+x} =(\frac{1}{729}) \\(\frac{1}{3})^{2+x} =(\frac{1}{3^7}) \\3^{-(2+x)}=3^{-7}\\-2-x = -7\\x = 5[/tex]
Hence the value of x is 5
Learn more on indices here: https://brainly.com/question/10339517