As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 46.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.

a. The salmon's acceleration
b. The magnitude of the force F during this interval N

Question

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Respuesta :

okpalawalter8 okpalawalter8 · Answer 1 · 2020-10-12T17:54:13+02:00

Answer:

a

[tex]a = 12.32 \ m/s^2[/tex]

b

[tex]F = 1017.52 \ N[/tex]

Explanation:

From the question we are told that

The length of the Chinook salmon is [tex]l = 1.50 \ m[/tex]

The mass of the Chinook salmon is [tex]m = 46.0 \ kg[/tex]

The upward velocity in water is [tex]u = 3.00 \ m/s[/tex]

The upward velocity in air is [tex]v = 5.80 \ m/s[/tex]

Generally from kinematic equations

[tex]v^2 = u^2 + 2as[/tex]

=> [tex] 5.80^2 = 3.00^2 + 2 * a * [ [\frac{2}{3} * l ][/tex]

=> [tex] 5.80^2 = 3.00^2 + 2 * a * [ [\frac{2}{3} * 1.5 ][/tex]

=> [tex] 5.80^2 = 3.00^2 + 2 * a * [1 ][/tex]

=> [tex]a = 12.32 \ m/s^2[/tex]

Generally magnitude of the force F during this interval in N is mathematically represented as

[tex]F = m (a + g )[/tex]

=> [tex]F = 46.0 (12.32 + 9.8 )[/tex]

=> [tex]F = 1017.52 \ N[/tex]