Answer:
d = 27.522 m
Explanation:
The horizontal speed of a pumpkin, [tex]v_x=4\ m/s[/tex]
The horizontal distance covered by the pumpkin, [tex]d_x=9.5\ m[/tex]
We can assume to find the the pumpkin's vertical displacement during the throw.
Firstly we can find the time of flight for the pumpkin. It can be calculated as follows :
[tex]t=\dfrac{d_x}{v_x}\\\\t=\dfrac{9.5}{4}\\\\t=2.37\ s[/tex]
The vertical displacement during the throw is given by :
[tex]y=u_yt+\dfrac{1}{2}a_yt^2[/tex]
Here, [tex]u_y=0\ \text{and}\ a_y=-g[/tex]
So,
[tex]y=\dfrac{1}{2}gt^2\\\\y=\dfrac{1}{2}\times 9.8\times (2.37)^2\\\\y=27.522\ m[/tex]
So, the vertical displacement of the pumpkin is 27.522 m.
