Answer:
The velocity of the frozen rock at [tex]t = 1.5\,s[/tex] is -14.711 meters per second.
Explanation:
The frozen rock experiments a free fall, which is a type of uniform accelerated motion due to gravity and air viscosity and earth's rotation effect are neglected. In this case, we need to find the final velocity ([tex]v[/tex]), measured in meters per second, of the frozen rock at given instant and whose kinematic formula is:
[tex]v = v_{o} + g\cdot t[/tex] (Eq. 1)
Where:
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]g[/tex] - Gravity acceleration, measured in meters per square second.
[tex]t[/tex] - Time, measured in seconds.
If we get that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]1.5\,s[/tex], then final velocity is:
[tex]v = 0\,\frac{m}{s}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (1.5\,s)[/tex]
[tex]v = -14.711\,\frac{m}{s}[/tex]
The velocity of the frozen rock at [tex]t = 1.5\,s[/tex] is -14.711 meters per second.
