Respuesta :

samueladesida43

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

Eduard22sly

The number of mole of the gas present in the cylinder is 0.02 mole

From the question given above, the following data were:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Number of mole (n) =?

The number of mole of the gas present in the cylinder can be obtained by using the ideal gas equation (PV = nRT) as illustrated below:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

1 × 1 = n × 0.0821 × 600

1 = n × 49.26

Divide both side by 49.26

[tex]n = \frac{1}{49.26}\\\\[/tex]

n = 0.02 mole

Thus, 0.02 mole of the gas is present in the cylinder.

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