Answer:
[tex]\frac{-17}{9}[/tex]
Step-by-step explanation:
You're not using the f(x) function for this problem.
Let's look at what the problem is asking. It says you must evaluate the function g(x) for 1/3. Basically, this means you plug in 1/3 every time there is an x.
So, your new equation is:
g([tex]\frac{1}{3}[/tex]) =([tex]\frac{1}{3}[/tex])^2 - 2
([tex]\frac{1}{3}[/tex])^2 = [tex]\frac{1}{9}[/tex]
To subtract two from this, you need a common denominator. This means we need to get -2 to have a denominator of 9. Multiply the numerator and denominator (1) by 9 to get [tex]\frac{-18}{9}[/tex].
Then, subtract.
[tex]\frac{1}{9}[/tex] [tex]\frac{-18}{9}[/tex] = -17/9.
