Respuesta :
Answer:
The mass of the second weight is approximately 0.477 kg
Explanation:
The given parameters are;
The acceleration experienced by the two weights = 3.8 m/s²
The mass of the first weight = 1.08 kg
The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;
[tex]a = \dfrac{g \cdot (M - m)}{M + m}[/tex]
Where;
a = The common acceleration of the two weights
g = The acceleration due to gravity = 9.81 m/s²
M = The mass of the first weight = 1.08 kg
m = The mass of the second weight
Therefore, we have;
[tex]m = \dfrac{M\cdot (g -a )}{g + a} = \dfrac{1.08\times (9.81 -3.8 )}{9.81 + 3.8} \approx 0.477[/tex]
The mass of the second weight = m ≈ 0.477 kg
The mass of the second weight ≈ 0.477 kg.
