what is the value of BC in the given triangle?

Answer:
BC = 1.2, Option B
Step-by-step explanation:
1). Apply Law of Cosine: [tex]c^2=a^2+b^2-2ab\cdot cos(\gamma)[/tex]
[tex]BC^2=AB^2+AC^2-2\cdot AB\cdot AC\cdot cos(\angle\ BAC)[/tex]
[tex]AB=2\\AC=1\\\angle BAC=25[/tex]
2). [tex]BC^2=2^2+1^2-2\cdot 1\cdot cos(25)[/tex]
[tex]BC=1.17[/tex]