Respuesta :

quasarJose

Answer:

BeO will have the greatest mass composition of oxygen

Explanation:

To solve this problem, we would find the mass composition of oxygen in each of the given sample.

To find this mass composition, let us derive the molecular mass of the given species;

  K₂O₂ = 2(39) + 2(16) = 110g/mol

  Na₂O = 2(23) + 16 = 62g/mol

   BeO = 9 + 16  = 25g/mol

Now; we know that mass of each sample is 1g;

mass composition of O in K₂O₂ = [tex]\frac{32}{110}[/tex] x  1= 0.29g

mass composition of O in Na₂O = [tex]\frac{16}{62}[/tex] x 1 = 0.26g

mass composition of O in BeO = [tex]\frac{16}{25}[/tex] x 1 = 0.64g

We can see that BeO will have the greatest mass composition of oxygen.

The mass composition of oxygen has been highest in BeO. Thus, option 3 is correct.

The molecular mass has been the mass of each element that has been present in the compound. The molecular mass of given compounds have been:

  • [tex]\rm K_2O_2[/tex] = 2(mass of K) + 2(mass of O)

= 2 (39) + 2 (16)

= 110 g/mol

  • [tex]\rm Na_2O[/tex]= 2(mass of N) + mass of O

= 2 (23) + 16

= 62 g/mol

  • BeO = mass of Be + mass of O  

= 9 + 16

= 23 g/mol

The mass composition of oxygen in 1 gram of the following compounds have been:

Mass composition = [tex]\rm \dfrac{Mass\;of\;Oxygen}{Molecular\;mass\;of\;compound}\;\times\;weight\;of\;sample[/tex]

  • [tex]\rm K_2O_2[/tex] = [tex]\rm \dfrac{32}{110}\;\times\;1\;gram[/tex]

[tex]\rm K_2O_2[/tex] = 0.29 grams

  • [tex]\rm Na_2O[/tex] = [tex]\rm \dfrac{16}{62}\;\times\;1\;gram[/tex]

[tex]\rm Na_2O[/tex] = 0.26 grams

  • BeO = [tex]\rm \dfrac{16}{23}\;\times\;1\;gram[/tex]

BeO = 0.64 grams.

The mass composition of oxygen has been highest in BeO. Thus, option 3 is correct.

For more information about the mass composition, refer to the link:

https://brainly.com/question/13531044

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