contestada

Solubility
Mixtures and Solutions
Acellus
If 1.23 g of chlorine gas dissolves in
0.95 L of water at 15.6 psi, at what
pressure (in psi) would you be able
to dissolve 1.89 g in the same
amount of water?

Respuesta :

ardni313

The pressure : 23.48 psi

Further eplanation

Henry's Law stated that the solubility of a gas is proportional to its partial pressure  

Can be formulated  

S = kH. P.  

S = gas solubility, mol / L  

kH = Henry constant, mol / L.atm  

P = partial gas pressure  

  • 1.23 g Cl₂

MW Cl₂ = 71 g/mol

mol of 1.23 g Cl₂ :

[tex]\tt mol=\dfrac{1.23}{71}=0.017[/tex]

Solubility O₂ : 0.017 mol/0.95 L =0.01789 mol/L

Henry's constant for O₂ :

P = 15.6 psi= 1.061517 atm

[tex]\tt S=kH.P\\\\kH=\dfrac{0.01789}{1,061517}=0.0169[/tex]

  • 1.89 g Cl₂

[tex]\tt \dfrac{1.89}{71}=0.026[/tex]

[tex]\tt S=0.026:0.95=0.027\\\\P=\dfrac{S}{kH}=\dfrac{0.027}{0.0169}=1.598~atm=23,48~psi[/tex]

Answer:24.0

Explanation:

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