Answer:
[tex]Section \: A. \\before \: the \: donation \ : jane \: had \: \boxed{18 \: (stuffed \: animals)} \\
Section B.\\
\boxed{the\: percentage\: of\: female\: student\: is\: \boxed{48 \%}}
[/tex]
Step-by-step explanation:
[tex]Section A.\\let \: the \: total \: animals \: be \to \: t_{a} \\ let \: the \: donated\: animals \: be \to \: d_{a} \\ then \to \\ if \: d_{a} = \frac{2}{3} (t_{a} ) : we \: can \: find \: t_{a} \: by \to \\ 12 = \frac{2}{3} (t_{a} ) \\ 2(t_{a} )= 12 \times 3 \\ t_{a} = \frac{36}{2} \\ \boxed{ t_{a} = 18.}
\\ \\
Section B.\\
let \: the \: total \: number\: of \: students\: be \: be \to \: t_{s} \\ let \: the \: number\: of \: male\: student\: be \: be \to \: m_{s} \\ then \to \\ if \: t_{s} = m_{s} +1 3 \: then \\
m_{s} = t_{s} -13\\
m_{s} = 25-13 \\
m_{s} =12 \\
hence \: percentage \: of \: girls \: is = \frac{12}{25} \times 100 \\
the \: percentage\: is \to \boxed{m_{s} = 48\%}
[/tex]
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