Respuesta :
Note: Consider we need to find the solution of given equation.
Given:
The equation is
[tex]\dfrac{1}{x}+\dfrac{x}{2}=\dfrac{11}{6}[/tex]
To find:
The solution of the equation.
Solution:
We have,
[tex]\dfrac{1}{x}+\dfrac{x}{2}=\dfrac{11}{6}[/tex]
[tex]\dfrac{2+x^2}{2x}=\dfrac{11}{6}[/tex]
By cross multiplication, we get
[tex]6(2+x^2)=11(2x)[/tex]
[tex]12+6x^2=22x[/tex]
[tex]6x^2-22x+12=0[/tex]
[tex]2(3x^2-11x+6)=0[/tex]
Divide both sides by 2.
[tex]3x^2-11x+6=0[/tex]
Splitting the middle term, we get
[tex]3x^2-9x-2x+6=0[/tex]
[tex]3x(x-3)-2(x-3)=0[/tex]
[tex](x-3)(3x-2)=0[/tex]
Using zero product property, we get
[tex]x-3=0[/tex] and [tex]3x-2=0[/tex]
[tex]x=3[/tex] and [tex]x=\dfrac{2}{3}[/tex]
Therefore, the solutions of the given equation are [tex]x=3[/tex] and [tex]x=\dfrac{2}{3}[/tex].
Quadratic equations are algebraic equations that can be factored or broken down into simpler forms(factors).
Transforming 1/x+x/2=11/6 to quadratic equations is 3x² - 11x + 6 = 0
We are given the algebraic equation: 1/x+x/2=11/6
Transforming it into a quadratic equation, we find the Lowest common denominator of the fractions in the quadratic equations.
LCD(x,2,6) = 6x
Multiply all through the fractions by 6x
(1/x * 6x)+ (x/2 * 6x) = (11/6 * 6x)
6 + 3x² = 11x
Rewriting the equation:
3x² - 11x + 6 = 0
Therefore, transforming 1/x+x/2=11/6 to quadratic equations is 3x² - 11x + 6 = 0
To learn more, visit the link below:
https://brainly.com/question/18251794
