jjazz
contestada

A player kicks a football from ground level with a velocity of
magnitude 27.0 m/s at an angle of 30° above the horizontal.
What is the horizontal distance the ball travels?
(hint: d= 1/2 at^2)

Respuesta :

samueladesida43

Answer:

37.33m

Explanation:

To calculate the distance using d= 1/2 at², the time taken for this projectile object (ball) must be calculated.

Time of a projectile = 2u sinθ/ g

Where u = velocity = 27m/s

g = 9.8m/s²

θ = 30°

T = 2usinθ/ g

T = 2 × 27 × sin 30°/9.8

T = 54sin30°/9.8

T = 27/9.8

T = 2.755

T = 2.76s

If the time taken for the ball to move is 2.76s, the distance travelled is:

D = 1/2at²

D = 1/2 × 9.8 × 2.76²

D = 1/2 × 9.8 × 7.6176

D = 74.65248/2

D = 37.33m

The horizontal distance the ball travels is 37.33m

The horizontal distance travel by ball is 37.32 meters.

First we have to calculate time of projectile,

               [tex]Time=\frac{2usin\theta}{g}[/tex]

Where g is acceleration due to gravity and u is velocity.

Given that, [tex]u=27m/s, \theta=30[/tex]

Substitute values in above relation.

       [tex]Time=\frac{2*27*sin30}{9.8}=\frac{2*27*0.5}{9.8}=2.76s[/tex]

The horizontal distance is given by,

              [tex]d=\frac{1}{2}gt^{2}\\ \\ d=\frac{1}{2}*9.8*(2.76)^{2} \\\\d=37.32m[/tex]    

Learn more about the projectile motion and velocity here:

https://brainly.com/question/1912408

Otras preguntas