Answer: The price of 1 football = $ 7 and price of 1 basket ball= $10
Step-by-step explanation:
Let x = price of 1 football.
y = price of 1 basketball.
As per given,
[tex]3x+2y=44\ \ \ (i)[/tex]
[tex]x+3y=31\ \ \ \ (ii)[/tex]
Multiply 3 to (ii) , we get
[tex]3x+9y=93\ \ \ \ (iii)[/tex]
Eliminate (i) from (iii)
[tex]7y=49\\\\\Rightarrow\ y=7[/tex]
Put this in (ii), we get
[tex]x+3(7)=31\\\\\Rightarrow\ x+21=31\\\\\Rightarrow\ x=31-21=10\\\\\Rightarrow\ x=10[/tex]
Hence, the price of 1 football = $ 7 and price of 1 basket ball= $10
