Answer:
Following are the solution to this question
Explanation:
please find the complete question in the attached file.
In point a:
The answer is "bottom".
In point b:
Using formula:
[tex]T= mg + \frac{m V^2}{2}[/tex]
[tex]\to 100= 0.2 \times 9.81 + \frac{0.2 \times V^2}{0.5}[/tex]
[tex]\to 100= 1.962+ \frac{0.2 + V^2}{0.5}\\\\\to 100- 1.962= \frac{0.2 + V^2}{0.5}\\\\\to 98.038= \frac{0.2 + V^2}{0.5}\\\\\to 49.019=0.2+V^2\\\\\to 48.819=V^2\\\\ \to 6.987 \ \frac{m}{s}[/tex]
