Answer:
Volume of water is 224mL
Explanation:
The heat that sample of copper reducing its temperature is the same heat that is absorbed from the water using the equation:
C(Cu)*m*ΔT = -C(water)*m*ΔT
Where C is specific heat of Copper and water, m is the mass and ΔT is change in temperature.
We need to solve the mass of water and as density of water is 1g/mL the mass in grams is equal to volume in mL
The copper change from 82.4°C to 24.9°C = 57.5°C
Mass of copper = 110g
Specific heat of copper and water is 0.385J/g°C and 4.18J/g°C, respectively.
Mass of water is our incognite and change in temperature of water is 22.3°C - 24.9°C = -2.6°C
Replacing:
C(Cu)*m*ΔT = -C(water)*m*ΔT
0.385J/g°C*110g*57.5°C = -4.18J/g°C*m*-2.6°C
224g = Mass of water
That means the volume of water is 224mL
