Answer:
The correct answer is "[tex]\frac{0.65}{V} \ percent[/tex]".
Explanation:
The given values are:
[tex]M_r=0.130 \ g[/tex]
[tex]M_o=20 \ g/L\times V(L)[/tex]
[tex]=20 \ V[/tex]
As we know,
⇒ [tex]Recovery \ percent=\frac{Amount \ of \ substance \ recovered}{Amount \ of \ substance \ originally \ taken}\times 100[/tex]
On substituting the given values, we get
[tex]=\frac{0.130}{20 \ V}\times 100[/tex]
[tex]=\frac{0.65}{V} \ percent[/tex]
Note: percent = %
