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How many milliliters of a 0.900% (m/v) normal saline solution can be prepared from 3.50 g of sodium chloride, NaCl

Respuesta :

dsdrajlin

Answer:

389 mL solution

Explanation:

Step 1: Given data

  • Concentration of the NaCl solution: 0.900% (m/v)
  • Mass of sodium chloride: 3.50 g
  • Volume of saline solution: ?

Step 2: Calculate the volume of saline solution

The concentration of the NaCl solution is 0.900% (m/v), that is, there are 0.900 g of NaCl every 100 mL of solution.

3.50 g NaCl × 100 mL solution/0.900 g NaCl = 389 mL solution

A solution is a special type of homogeneous mixture composed of two or more substances. In such a mixture, a solute is a substance dissolved in another substance, known as a solvent

The definition of the solute and solvent is:-

  • Solute- A component that is less in solution
  • Solvent - A component that is more in solution

The data given in the NaCl solution is: 0.900% (m/v)

Mass of sodium chloride: 3.50 g

Volume of saline solution: ?

The concentration of the NaCl solution is 0.900% (m/v), that is, there is 0.900 g of NaCl every 100 mL of solution.

[tex]\frac{3.50 * 100}{0.900} = 389 mL solution[/tex]

Hence, 389ml is required.

For more information, refer to the link:-

https://brainly.com/question/1602374

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