Answer:
[tex]L=1.07\ \mu H[/tex]
Explanation:
Given that,
No of turns in a coiled telephone cord is 65
The diameter of the coil, d = 1.3 cm = 0.013 m
Radius, r = 0.0065 m
Unstretched length of the coil, l = 65.5 cm = 0.655 m
We need to find the inductance of one conductor in the unstretched cord. The formula for the inductance is given by :
[tex]L=\dfrac{\mu_oN^2 A}{l}\\\\L=\dfrac{4\pi \times 10^{-7}\times (65)^2\times \pi (0.0065)^2}{0.655 }\\\\L=1.07\times 10^{-6}\ H\\\\L=1.07\ \mu H[/tex]
So, the inductance of one conductor in the unstretched cord is [tex]1.07\ \mu H[/tex].
