Respuesta :
Given:
Seed below the ground = [tex]3\dfrac{1}{4}\text{ in.}[/tex]
Total length of plant = [tex]11\dfrac{1}{2}\text{ in.}[/tex]
To find:
The length of plane above the ground.
Solution:
We have,
Plant below the ground = [tex]3\dfrac{1}{4}\text{ in.}[/tex]
Total length of plant = [tex]11\dfrac{1}{2}\text{ in.}[/tex]
Plant above the ground = Total length of plant - Plant below the ground
[tex]=11\dfrac{1}{2}-3\dfrac{1}{4}[/tex]
[tex]=\dfrac{11\times 2+1}{2}-\dfrac{3\times 4+1}{4}[/tex]
[tex]=\dfrac{22+1}{2}-\dfrac{12+1}{4}[/tex]
[tex]=\dfrac{23}{2}-\dfrac{13}{4}[/tex]
Taking LCM, we get
[tex]=\dfrac{46-13}{4}[/tex]
[tex]=\dfrac{33}{4}[/tex]
[tex]=8\dfrac{1}{4}[/tex]
Therefore, the length of plant above the ground is [tex]8\dfrac{1}{4}\text{ in.}[/tex]
