Answer:
The answer is "0.35".
Explanation:
please find the complete question in the attached file.
Mass of [tex]CH_3C0_2 H[/tex][tex]= 77 \ g \\\\[/tex]
Molar mass of [tex]CH_3C0_2 H[/tex] [tex]= 60.05 \ \frac{g}{mol} \\\\[/tex]
No of moles in [tex]n_{CH_3CO_2H}[/tex] [tex]= 77 \ g \times \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}[/tex]
[tex]= 1.28 \ mol \ CH_3CO_2H[/tex]
Mass of water [tex](H_2O)[/tex][tex]= 42 \ g[/tex]
The molar mass of water [tex](H_2O)[/tex][tex]= 18.02 \ \frac{g}{mol}[/tex]
moles of water [tex]n_{H_2O}[/tex]:
[tex]= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O[/tex]
Molfraction of acetic acid:
[tex]X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\[/tex]
[tex]=\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35[/tex]
