Answer:
The correct solution will be "12.48 in/s²".
Explanation:
The given values are:
Angular speed
= 79.0 rev/min
Time
= 3.80 seconds
Now,
⇒ [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]
[tex]=\frac{8.2}{3.8}[/tex]
[tex]=2.1 \ rad/s^2[/tex]
Tangential acceleration will be:
= [tex]Angular acc.\times radius[/tex]
= [tex]2.1\times 6.5\times 0.0254[/tex]
= [tex]0.3467 \ m/s^2[/tex]
= [tex]12.48 \ in/s^2[/tex]
