Answer: The monoatomic ions formed by bromine and rubidium are [tex]Br^-[/tex] and [tex]Rb^+[/tex] respectively.
Explanation:
When an atom accepts an electron negative charge is created on atom and is called as anion. When atom loses an electron positive charge is created on atom and is called as cation.
The atomic number of bromine and rubidium is 35 and 37 respectively. So, the number of electrons is equal to 35 and 37 respectively. Bromine will gain one electron and rubidium will lose one electron to attain stable electronic configuration to form [tex]Br^-[/tex] and [tex]Rb^+[/tex] respectively.
[tex]Br:35:1s^22s^22p^63s^23p^64s^23d^{10}4p^5[/tex]
[tex]Br^-:36:1s^22s^22p^63s^23p^64s^23d^{10}4p^6[/tex]
[tex]Rb:37:1s^22s^22p^63s^23p^64s^23d^{10}4p^63s^1[/tex]
[tex]Rb^+:36:1s^22s^22p^63s^23p^64s^23d^{10}4p^6[/tex]
