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Large chocolate bar has a base area of 48.96 square feet and its length is 0.6 foot shorter than twice its width. Find the length and width 

Respuesta :

samuelonum1

Answer:

Length=9.6

Width=5.1

Step-by-step explanation:

Step one:

given data

for the large chocolate

Area=48.96ft^2

let the width be x

w=xft

let the length be l

l=(2x-0.6)

Step two:

we know that area A=length * width

48.96=(2x-0.6)*x

48.96=2x^2-0.6x

2x^2-0.6x-48.96=0

divide through by 2 we have

x^2-0.3x-24.48=0

solving the quadratic equation, the roots are

x=5.1

x=-4.8-----not correct cannot be -ve

so x=5.1

the width is 5.1

the length = 2(5.1)-0.6

l=10.2-0.6

l=9.6

check Area= 9.6*5.1= 48.96

abidemiokin

The length and the width of the bar are 6.7ft and 7.3ft respectively

The formula for calculating the volume of the chocolate bar is expressed as:

  • V = Base area * height

Given the following parameters

  • Base area = 48.96 square feet
  • B = length * width
  • 48.96 square feet = lw

If the length is 0.6 foot shorter than twice its width, hence;

l = w - 0.6

The expression becomes;

[tex]48.96 = w(w-0.6)\\48.96 = w^2 - 0.6w\\w^2 - 0.6w - 48.96 - 0[/tex]

On factorizing the result, w = 7.3ft

Recall that l = w - 0.6

l = 7.3 - 0.6

l = 6.7ft

Hence the length and the width of the bar are 6.7ft and 7.3ft respectively.

Learn more here: https://brainly.com/question/2607596

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