Answer:
Paint required will be 2.06gallons
Step-by-step explanation:
The given dimensions are
Height - 8ft
Width - 7 [tex]\frac{11}{12}[/tex] = 7.9ft
Length - 9. 83ft
To calculate the the amount of paint required to paint the walls we need to find the area of the walls
wall 1 = height * width of room= 8 * 7.9 = 63.28[tex]ft^2[/tex]
wall 2 = height * length = 8*9.83 = 78.64 [tex]ft^2[/tex]
The total area of the 4 walls will be = 2*(63 .28+78.64)= 283.84[tex]ft^2[/tex]
ceiling area = 77.66[tex]ft^2[/tex]
total area to be painted = 283.84 + 77.66 = 361.50[tex]ft^2[/tex]
One gallon of paint covers 350 [tex]ft^2[/tex] of area
so 361.50 [tex]ft^2[/tex] area will be covered by = 361.5/350 = 1.03gallons of paint
also we need two coating so the paint required will be = 1.03 * 2 =2.06gallons