Answer:
The time taken for the apple to reach the ground is 0.9 s
Explanation:
Given;
height of the apple tree, h = 4 m
acceleration due to gravity, g = 9.8 m/s²
The time taken for the apple to reach the ground is given by;
[tex]h = \frac{1}{2}gt^2\\\\t^2 = \frac{2h}{g}\\\\t = \sqrt{\frac{2h}{g}}\\\\t = \sqrt{\frac{2*4}{9.8}}\\\\t = 0.9 \ s[/tex]
Therefore, the time taken for the apple to reach the ground is 0.9 s
