Respuesta :
Answer:
try:
size = int(input("Enter a number: "))
except ValueError:
print("must be a number")
if size==0:
print("number must be greater than zero.")
elif size%2==0:
print("number must be odd.")
else:
obj = '#'
mid_size = round(size/2)
s = size - mid_size
count = 2
counts = 1
for i in range(size+1):
if i<=mid_size:
print(" " *(size - i) + (obj+" ") * i)
elif i>mid_size:
print(" " * (s + counts) + (obj + " ") * (i - count))
count += 2
counts += 1
Explanation:
The python source code uses a try and except statement to check for value error and print a diamond shape of the object "#" determined by the input number.
