10.8 moles of H₂SO₄ is required for the reaction.
The balanced equation for the reaction is given below:
2Al + 3H₂SO₄ —> Al₂(SO₄)₃ + 3H₂
From the balanced equation above,
2 moles of Al required 3 moles of H₂SO₄.
Finally, we shall determine the number of mole of H₂SO₄ required to react with 7.20 moles of Al.
This can be obtained as follow:
From the balanced equation above,
2 moles of Al required 3 moles of H₂SO₄.
Therefore,
7.20 moles of Al will require = [tex]\frac{7.2 X 3}{2} \\\\[/tex] = 10.8 moles of H₂SO₄
Thus, 10.8 moles of H₂SO₄ is required for the reaction.
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